(2^2x+1)-33*(2^x-1)+4=0

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Solution for (2^2x+1)-33*(2^x-1)+4=0 equation: 



(2^2x+1)-33(2^x-1)+4=0

We multiply parentheses

(2^2x+1)-66x+33+4=0

We get rid of parentheses

2^2x-66x+1+33+4=0

We add all the numbers together, and all the variables

-66x+2^2x+38=0

We move all terms containing x to the left, all other terms to the right

-66x+2^2x=-38

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